A 95 g ball is launched from ground level at an angle 30 ? above the horizon. It

Question

A 95g  ball is launched from ground level at an angle 30? above the horizon. Its initial speed is 23m/s .
A.What are the values of px and py an instant after the ball is launched?
B.What are the values of px and py at the point of maximum altitude?
C.What are the values of px and py an instant before the ball hits the ground? A 95g  ball is launched from ground level at an angle 30? above the horizon. Its initial speed is 23m/s .
A.What are the values of px and py an instant after the ball is launched?
B.What are the values of px and py at the point of maximum altitude?
C.What are the values of px and py an instant before the ball hits the ground? A 95g  ball is launched from ground level at an angle 30? above the horizon. Its initial speed is 23m/s .
A.What are the values of px and py an instant after the ball is launched?
B.What are the values of px and py at the point of maximum altitude?
C.What are the values of px and py an instant before the ball hits the ground? A 95g  ball is launched from ground level at an angle 30? above the horizon. Its initial speed is 23m/s .
A.What are the values of px and py an instant after the ball is launched?
B.What are the values of px and py at the point of maximum altitude?
C.What are the values of px and py an instant before the ball hits the ground?

Explanation / Answer

A) Px =M*Vx = M*V*cos30 = 0.095*23*cos30 = 1.89 kg m /s

Py = M*Vy = M*V*sin30 = 0.095*23*sin30 = 1.09 kg m /s

B) Px= M*Vx = M*V*cos30 = 0.095*23*cos30 = 1.89 kg m /s

Py = M*Vy = M *0 = 0

C) Px =M*Vx = M*V*cos30 = 0.095*23*cos30 = 1.89 kg m /s

Py = M*-Vy = -M*V*sin30 = 0.095*23*sin30 = -1.09 kg m /s

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