A chain consists of 5 links, each having a mass of 0.112 kg. The chain is being

Question

A chain consists of 5 links, each having a mass of 0.112 kg. The chain is being pulled upward by a force applied by your hand to its top link, giving the chain an upward acceleration of 2.65 m/s2.     (a) Find the force magnitude F exerted on the top link by your hand.
      N

    (b) Find the net force on each link.
                                                 N

    (c) Find the magnitude of the force that each link exerts on the link below it.              

Explanation / Answer

M = 5*m = 5*0.112 = 0.56 kg
a = 2.65 m/s^2

a)Fnet = M*g + M*a = M(g+a) = 0.56*(9.8+2.65) = 6.972 N

b)

F = m*a = 0.112*2.65 = 0.2968 N

c)

F_link2 = 4*m*(g+a) = 5.5776N

F_link3 = 3*m*(g+a) = 4.1832N

F_link4 = 2*m*(g+a) = 2.7888N

F_link5 = 1*m*(g+a) = 1.3944N

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