A chain consisting of five links, each of mass 0.092 kg, is lifted vertically wi

Question

A chain consisting of five links, each of mass 0.092 kg, is lifted vertically with a constant acceleration of 2.41 m/s^2, as shown in Fig. 3-35. (a) Find the force acting between the bottom link and the next one up. 1.12 N Find the force acting between the second link from the bottom and the one above it. N Find the force acting between the third link from the bottom and the one above it. N Find the force acting between the fourth link from the bottom and the one above it. N (b) Find the force F exerted on the top link by the agent lifting the chain. N (c) Find the net force on each link. 0.22 N

Explanation / Answer

We consider link1 is the lowest and link5 topmost.

(a)

Force on link1 from link2 = 0.092*2.41 + 0.092*9.81 = 1.12424 N

(b)

Force on link2 from link3 = 1.12424 + 0.092*9.81 + 0.092*2.41 = 2.24848 N

(c)

Force on link3 from link4 = 2.24848 +0.092*9.81 + 0.092*2.41 = 3.37272 N

(d)

Force on link4 from link5 = 3.37272 + 0.092*9.81 + 0.092*2.41 = 4.49696 N

(e)

Force on link5 from the person = 4.49696 + 0.092*9.81 + 0.092*2.41 = 5.6212 N

(f)

Net force accelerating each link = 0.092*2.41 = 0.2217 N

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