A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant an

Question

A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 0.600 rad/sec2, then the total acceleration of a point 3.00 cm from the center of the CD after 1.30 sec is 0.0415 m/s2. 0.0502 m/s2. 0.0256 m/s2. 0.0472 m/s2. 0.0306 m/s2. A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 0.600 rad/sec2, then the total acceleration of a point 3.00 cm from the center of the CD after 1.30 sec is 0.0415 m/s2. A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 0.600 rad/sec2, then the total acceleration of a point 3.00 cm from the center of the CD after 1.30 sec is 0.0415 m/s2. A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 0.600 rad/sec2, then the total acceleration of a point 3.00 cm from the center of the CD after 1.30 sec is 0.0415 m/s2. A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 0.600 rad/sec2, then the total acceleration of a point 3.00 cm from the center of the CD after 1.30 sec is 0.0415 m/s2. 0.0502 m/s2. 0.0256 m/s2. 0.0472 m/s2. 0.0306 m/s2. 0.0502 m/s2. 0.0256 m/s2. 0.0472 m/s2. 0.0306 m/s2. 0.0502 m/s2. 0.0256 m/s2. 0.0472 m/s2. 0.0306 m/s2. 0.0306 m/s2. 0.0306 m/s2.

Explanation / Answer

angular velocity w after 1.3 sec=0.6*1.3=0.78rad/s

so total accelration=tangential acc + centripetal acc=((w^2*r)^2 + (ar)^2)^0.5

=((0.78^2*0.03)^2+(0.6*0.03)^2)^0.5=0.02563m/s2

so answer is 0.0256 m/s2

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