In the figure shown, C1=C5= 9.0uF and C2=C3=C4= 4.9uF. The applied poetential is

Question

In the figure shown, C1=C5= 9.0uF and C2=C3=C4= 4.9uF. The applied poetential is Vab= 210V.  Find:

1) The total equivalent capacitance of the network between points a and b.

2) Find the Charge "Q", the Voltage "V", and the energy "U" on each of the capacitances (C1 thorough C5).

if figure is not shown, here is a link: http://session.masteringphysics.com/problemAsset/1436135/2/YF-24-59.jpg

Thanks.

In the figure shown, C1=C5= 9.0uF and C2=C3=C4= 4.9uF. The applied poetential is Vab= 210V. Find: The total equivalent capacitance of the network between points a and b. X Find the Charge "Q", the Voltage "V", and the energy "U" on each of the capacitances (C1 thorough C5).

Explanation / Answer

1.c3 and c4 are in series

2.equivalent of these two is =c3*c4/[c3+c4]=2.45 uF

now this is in parallel with the c2

then equivalent is =2.45+c2=7.35 uF

3.now above 7.35 uF is in series with the c1 and c5

now equivalent capacitance between a and b=1/[1/c1+1/c5+1/7.35]=2.7911 uF

Vab=210 v

total charge =cv=5.86*10^-4 coloumbs

2]

parallel capacitors are equal in charge but different voltage

when we caliculating equivalent capacitance in third step

7.35 uF is in series with the c1 and c5

now these having same charge i.e 5.86*10^-4 c

charge on c1=5.86*10^-4 c

voltage on c1=q/c=5.86*10^-4/9 *10^-6=65.1265 v

energy=1/2cv^2=19.0865*10^-3 J

cgarge on c5=5.86*10^-4 c

voltage on c5=q/c=65.1265 v

energy=19.0865*10^-3 J

now we need to find for c2,c3 and c4

voltage on c2 is 65.12655+65.1265-210=79.747 v

charge=vc=3.907*10^-4 c

energy=0.5*c*v^2=15.5809*10^-3 J

now c2 is in parallel with combination of c3 and c4

voltage across c2 is same as combination c3 and c4 i.e 79.747 v

it is equally divided between two capaciters because they having same capacitance value.

such that voltage on c3=39.8735 v

on c4=39.8735 v

charge on c3=vc=1.953875*10^-4 c

energy=7.791*10^-3 J

charge on c4=1.953875*10^-4 c

energy=7.791 *10^-3 J

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.