In the figure is an electric dipole, with -5 V applied to the negative conductor

Question

In the figure is an electric dipole, with -5 V applied to the negative conductor, shown on the left-side and +5 V applied to the positive conductor, shown on the right-side. With the voltage applied between the conductors, the resulting equipotential lines are mapped out. Accurately draw the electric field lines between the two conductors. Consider a changed particle, q_0 with a change of + 0.001 C and a mass of 2 X 10^-5 kg moving between the conductors. When answering the following questions justify your answers and show all your work. What is the work done on q_0 as it moves from point A to point B? Be sure to consider the magnitude and sign, if necessary, of the work done. Now if q_0 is released from rest at point B what is its speed when it reaches point A? What is the work done on q_0 as it moves from point C to point D? Be sure to consider the magnitude and sign, if necessary, of the work done. What is magnitude of the work done on q_0 if it were to move between the points of maximum potential difference?

Explanation / Answer

a) lines which you have drawn are correct.

b) Workdone(A to B) = q*dV

= q*(vA - vB)

= 0.001*(-2.5 - 0)

= -0.0025 J

c) Workdone(B to A) = +0.0025 J

now Apply, W = 0.5*m*v^2

==> v = sqrt(2*W/m)

= sqrt(2*0.0025/(2*10^-8))

= 500 m/s

d) Workdone(C to D) = q*(Vc - VD)

= 0

e) maximum potentail diffrence = +2.5 - (-2.5)

= 5 volts

so, magnitude of maximum work = q*dV

= 0.001*5

= 0.005 J

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