A loaded penguin sled weighing 70 N rests on a plane inclined at angle ? = 20 A

Question

A loaded penguin sled weighing 70 N rests on a plane inclined at angle ? = 20

A loaded penguin sled weighing 70 N rests on a plane inclined at angle ? = 20 degree to the horizontal (see the figure). Between the sled and the plane, the coefficient of static friction is 0.29, and the coefficient of kinetic friction is 0.13. (a) What is the minimum magnitude of the force , parallel to the plane, that will prevent the sled from slipping down the plane? (b) What is the minimum magnitude F that will start the sled moving up the plane? (c) What value of F is required to move the sled up the plane at constant velocity?

Explanation / Answer

a) F =mgsin 20 - usmgcos20 = 234.63-186.94 = 47.69 N

b) 47.69 N

c) F = mgsin 20 - ukmgcos20 = 234.63-83.8 = 150.83 N

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