The block in the figure is initially at rest on an inclined plane at the equilib

Question

The block in the figure is initially at rest on an inclined plane at the equilibrium position that it would have if there were no friction between the block and the plane.

A) How much work is required to move the block 25cm down the plane if the frictional coeffcient is ?=0

B)How much work is required to move the block 25cm down the plane if the frictional coefficient is ? = 0.19?

The block in the figure is initially at rest on an inclined plane at the equilibrium position that it would have if there were no friction between the block and the plane. How much work is required to move the block 25cm down the plane if the frictional coefficient is ?=0 How much work is required to move the block 25cm down the plane if the frictional coefficient is ? = 0.19?

Explanation / Answer

A) W = 0.5*K*x^2 = 0.5*40*0.25^2 = 1.25 J

B) W = 0.5*K*x^2+ mue*m*g*cos30*s =( 0.5*40*0.25^2 (+ (0.19*2*9.8*cos30*0.25) = 2.056 J

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