A force of F = 75 N is used to drag a crate d = 7 m across a floor. The force is

Question

A force of F = 75 N is used to drag a crate d = 7 m across a floor. The force is directed at an angle upward from the crate so that the vertical component of the force is Fv = 45 N and the horizontal component is Fh = 60 N as shown in the diagram.

A force of F = 75 N is used to drag a crate d = 7 m across a floor. The force is directed at an angle upward from the crate so that the vertical component of the force is Fv = 45 N and the horizontal component is Fh = 60 N as shown in the diagram. What is the work done by the horizontal component of the force? What is the work done by the vertical component of the force? What is the total work done by the 75-N force?

Explanation / Answer

a)work done=f.d=fdcos(theta)

                  W=60*7*cos(0)=420N

b) work done by vertical component of force

W=fdcos(theta)=45*7*cos(90)=0N

c) work done by net force 75N

W=420+0=420N

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