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The Electric Field is constant, with a magnitude of 80 V/m , and is directed par

ID: 2137369 • Letter: T

Question

The Electric Field is constant, with a magnitude of 80 V/m, and is directed parallel to the +X-axis. The potential at point 1 is 1200 V. .





The figure below shows two points in an E-field: Point 1 is at (X1,Y1) = (3,4) in m, and Point 2 is at (X2,Y2) = (12,9) in m. The Electric Field is constant, with a magnitude of 80 V/m, and is directed parallel to the +X-axis. The potential at point 1 is 1200 V. calculate the potential at point 2 Calculate the work required to move a negative charge of Q = -470 micro C from point 1 to point 2.

Explanation / Answer

A) V =V0- E*d ( here d is the perpendicualr distance ie x)

=> V = 1200 - (80*(12-3)) = 480 V

B ) work = del(V)*q = (480-1200)*-470*10^-6 = 0.3384 J


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