I got the first part of this question right can someone help me with the rest. A

Question

I got the first part of this question right can someone help me with the rest. Also if you could show me how to do it that would be great!!

A 0.840- kg glider on a level air track is joined by strings to two hanging masses. As seen in the figure, the mass on the left is 4.85 kg and the one on the right is 3.62 kg The strings have negligible mass and pass over light, frictionless pulleys. Find the acceleration of the masses when the air flow is turned off and the coefficient of friction between the glider and the track is 0.43. Take positive to be an acceleration to the right.
-9.15

Explanation / Answer

M1 g - T1 = M1 a         acceleration of 4.85 kg mass

T2 - M2 g = M2 a         acceleration of 3.62 kg mass

T2 - T1 + (M1 - M2) g = (M1 + M2) a

T1 - T2 - u m g = m a      acceleration of glider

-u m g - m a + (M1 - M2) g = (M1 + M2) a      eliminating (T2 - T1)

a = (M1 - M2 - u m) g / (M1 + M2 + m)

a = (4.85 - 3.62 - .43 * .84) / (4.85 + 3.62 + .84) g = .933 g = .915 m/s^2

We chose acceleration to left so a = -.915 m/s^2

Now just substitute a into the first two equations to calculate T1 and T2

(using the positive value for a)

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