I got part A of this question figured out, when I moved topart B I got stuck. I

Question

I got part A of this question figured out, when I moved topart B I got stuck. I have a nagging feeling it's something simpleI am missing or not remembering.... Q: Two cars travel in the same direction along a straighthighway one at constant speed of 55 mph and the other at 70 mph.(A) Assuming they satrat at the same point, how much sooner doesthe faster car arrive at a destination 10 miles away. (B) How far must the faster car travel before it has a15 minute lead on the slower car? Car 2 is traveling 2.34 minutes faster than car one, accordingto my calculations. Any help, even an equation to point me in the right directionwould be much appreciated! Thanks :o) I got part A of this question figured out, when I moved topart B I got stuck. I have a nagging feeling it's something simpleI am missing or not remembering.... Q: Two cars travel in the same direction along a straighthighway one at constant speed of 55 mph and the other at 70 mph.(A) Assuming they satrat at the same point, how much sooner doesthe faster car arrive at a destination 10 miles away. (B) How far must the faster car travel before it has a15 minute lead on the slower car? Car 2 is traveling 2.34 minutes faster than car one, accordingto my calculations. Any help, even an equation to point me in the right directionwould be much appreciated! Thanks :o) Car 2 is traveling 2.34 minutes faster than car one, accordingto my calculations. Any help, even an equation to point me in the right directionwould be much appreciated! Thanks :o)

Explanation / Answer

you need to set up equations for their positions: Xa=55*t Xb=70*t we want to know when Xa+15min=Xb so we have 55*(t+.25)=70*t, t=.917 hours Xb=70*.917=64.2 miles

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