I got Q value of 1.13735417MeV/sec Delta M: 1.221x10^ -3 not sure if what I did

Question

I got Q value of 1.13735417MeV/sec

Delta M: 1.221x10^ -3

not sure if what I did was correct. Not sure how to get to Nuclei/sec

The radioactive carbon isotope, 146C, is produced in the Earth's atmosphere by the nuclear reaction shown below. All necessary masses are given. In 2012. the power output in the atmosphere for this reaction was measured to be 106 W. At what rate (in units of nuclei/s) was 146C produced in the atmosphere irt 2012? (15) 9.98 times 1018 nuclei/s 147N + 10n rightarrow 146C + 11P

Explanation / Answer

Power = Energy / time

but

Energy = energy emitted for single nucleus x No of nuclei

So Power = energy emitted for single nucleus x No of nuclei / time

No of nuclei / time = Power / energy emitted for single nucleus

mass defect = 14.003242 + 1.007276 - 1.008665 - 14.003074

Mass defect = 1.221 x 10-3

energy per nuclues = 1.22x 10-3 x 931.5

energy per nuclues = 1.13736 MeV

energy per nucleus = 1.13736 x 1.9 x 10-13 J

1 Me V = 1.6 x 10-13 J

Q = 1.81977 x 10-13 J

So No of nuclei / time = 10^6 / 1.81977 x 10-13

rate = 5.495 x 10^18

so the rate is 5.495 x 10^18 nuclei / sec

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