The figure below is a long, massless stick with evenly spaced marks. The distanc
ID: 2136846 • Letter: T
Question
The figure below is a long, massless stick with evenly spaced marks. The distance between two adjacent marks is 10.10 cm. In each of the following problems a pivot will be placed at a point on the stick. The pivot will hold that point fixed, but allow the stick to rotate. You will be finding conditions that will keep the stick in static equilibrium given different forces. All forces will be applied to the stick perpendicular to the length of the stick.
1. A pivot is placed at Point E and a force of 17.0 N is directed downward perpendicular to the stick at Point A. What is the magnitude and direction of the force which must be applied at point L in order to obtain static equilibrium?
2. A pivot is placed at Point K and a force of 31.0 N is directed downward perpendicular to the stick at Point A. What is the magnitude and direction of the force which must be applied at point C in order to obtain static equilibrium?
3. A pivot is placed at Point A and a force of 15.0 N is directed downward perpendicular to the stick at Point D. One at a time, each of the following 3 forces are applied to the stick in the manner described. Where must these forces be applied in order to achieve static equilibrium? If there is no point that will work within reason, select the option none.
A. A force of 15.0 N directed downward perpendicular to the stick.
B. A force of 6.7 N directed upward perpendicular to the stick.
C. A force of 20.0 N directed upward perpendicular to the stick.
Explanation / Answer
(1) 17 * (E-L) = F * (J-L)
17* 4 = F * 3
F = 22.666 down
(2) 31 * (G-E) = (G-F) * F
31 * 8 = 6 * F
F = 41.333 up
(3) 15 * (B-D) = 15(D-X)
15* 2 = 15 (D-X)
(D-X) = 2
X = K down
(4) 15 * 2 = 6.7 (D-X)
(D-X) = 4.47
X = Doesn't exist (None)
(5) 15 * 2 = 20(D-X)
(D-X) = 1.5
X = H up
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