batter baseball leaves the bat at an angle of 35.0 above horizontal and is caugh

Question

    batter baseball leaves the bat at an angle of 35.0 above horizontal and is caught by an outfielder 350 ft from home plate at the same height from which it left the bat.

a.  what is the initial speed

b. how high does the ball rise above the point where it struck the bat

2. a physics book slides off a horizontal tabletop with a speed of 3.10m/s it  strikes the floor at 0.350s ignore resistance. find the height of the tabletop above the floor.

find the horizontal distance from the edge of the table to the point where the book strikes the floor.

find the horizontal component of the book's velocity just before the book reaches the floor

find the vertical component of the book's velocity just before the book reached the floor.

THANKS for any help the teacher is out and we have a sub but the work is still due tonight.

Explanation / Answer

1)

350 ft =106.68 m

Range = (u^2/g) * sin2?

Therefore

106.68 = (u^2/9.8)*sin(70)

Therefore u = 33.3550528515 m/sec

H = u2sin2?/(2g) = 18.6745350441m

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