Q1) What is the change in the potential energy of the mass as it goes up the inc

Question

Q1) What is the change in the potential energy of the mass as it goes up the incline ?   J

Q2) What is the min force requuired to pull the mass along the surface of the incline to the top of the incline ? N

Q2.2) How much work would be done by that force ? J

Q3a ) What isw the kinetic energy at that time ? J

Q3b) what percentage of the potential energy of the system is not coverted into kinetic energy due to friction ? %

Q4 Heigeht ab oev the ground ?

Q4b) what a person who weighs more than 150lb have to go higher, go lower or go to the same height to obtain the same amount of potential energy?

A 0.40 Kg mass moves up 40 centimeters along an incline. The vertical height of the incline is 7 centimeters. What is the change in the potential energy of the mass as it goes up the incline? J A 0.40 Kg mass moves up 40 centimeters along an incline. The vertical height of the incline is 7 centimeters What is the minimum force required to pull the mass along the surface of the incline to the top of the incline? N How much work would be done by that force? J A 0.40 kg mass moves down 40 centimeters along an incline. The vertical height of the incline is 7 centimeters. The mass is released from the top of the incline and slides down. The maximum velocity ( taken the instant before the mass reaches the bottom of the incline ) is 1.00 m /s. Some of the initial potential energy is lost due to friction. What is the kinetic energy at that time? J What percentage of the potential energy of the system is not converted into kinetic energy due to friction? % How many meters above the ground would an average person (150 lb.) have to climb to gain 2180 joules of potential energy? We usually measure our weight (F = mg) in pounds. For conversions, you may need to know that 1 pound of weight is equal to 4.448 Newtons. Height above the ground m Would a person who weighs more than 150 lb. have to go higher, go lower or go to the same height to obtain the same amount of potential energy? The same height Lower Higher

Explanation / Answer

1)

change in potential energy=mgh

=0.4*9.8*0.07

=0.2744J

2)

minimum force required to pull the mass =component of gravitational force along the incline

=mg*cos(@) (@ is the inclination angle of plane)

=0.4*9.8*0.98456

=3.8595N

2.2)

workdone by force =force*displacement

=3.8595*o.4

=1.5438J

3a)

kinetic energy at that time=mv^2/2

=0.4*1/2

=0.2J

3b)

percentage of potential energy lost=(0.2744-0.2)*100/0.2744

=27.1137%

4)

150 lb=68.0389kg

potential energy=mgh

mgh=2180

68.0389*9.8*h=2180

h=3.2694m

height to be climbed over the ground=3.2694m

4b)

at constant potential enegy height is inversly propotinal to mass

so as mass increases height decreases

so the person who weighs more than 150 lb should climb lower height to get same potential energy

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