A bullet shot horizontally, initial speed is 500m/s. Fired from 5 feet above gro

ID: 2135559 • Letter: A

Question

A bullet shot horizontally, initial speed is 500m/s. Fired from 5 feet above ground.

How far will it go til it hits the ground?

How long is it in the air?

Maximum altitude?

Speed when it hits ground

Same bullter at 45 degree angle above horizontal

Max height?

Horizontal distance?

Time in flight?

In first problem, what should be the velocity of the bullet in order not to fall to the ground at all? Assuming Earth radius to be R= 6400km

How much is the acceleration?

Must show me equations to solve with solution.

range R=u*sqrt(2*h/g)=278.84 m.....

time of flight =sqrt(2*h/g)=0.557 sec...

speed V=sqrt(u^2+g^2*t^2)=500m/sec..

altitude is zero.....

max.height =Hm,ax=u^2 sin^2(45)/2*g=6377.55 m..

range R= u^2 sin(2*45)/g =25510.2 m...

Time of flight T=2*u sin(45)/g=72.16 sec..

. escape velocity Ve=sqrt(2*g*R) =11.2 km/sec

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