A bullet train leaves a train station and accelerates with 1 g for 60 seconds. O
ID: 1879508 • Letter: A
Question
A bullet train leaves a train station and accelerates with 1 g for 60 seconds. Once up to speed it moves with constant speed for another 60 seconds. How far has the train traveled over this trip?I don’t know what to do when it comes to constant speed! A bullet train leaves a train station and accelerates with 1 g for 60 seconds. Once up to speed it moves with constant speed for another 60 seconds. How far has the train traveled over this trip?
I don’t know what to do when it comes to constant speed!
I don’t know what to do when it comes to constant speed!
Explanation / Answer
accelerates with 1 g for 60 seconds
a = 9.8 m/s2
t = 60 sec
s = vot + 1/2at2
s = 0 + (0.5*9.8*602)
d1 = s = 17640 m
v = v0 + at
v = 0 + (9.8*60)
v = 588 m/s
constant speed for another 60 seconds
d2 = v*t
d2 = 588*60
d2 = 35280 m
total trip = 17640 + 35280 = 52920 m
total trip = 52.92 km
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