The Moon orbits the Earth in an approximately circular path. The velocity of the

Question

The Moon orbits the Earth in an approximately circular path. The velocity of the moon as a function of time is given by:

A. t=0 to t= 0.500 days

B. t=0 to t=0.0050days

vx = ?v sin(?t) vy = v cos(?t) The Moon orbits the Earth in an approximately circular path. The velocity of the moon as a function of time is given by: where v = 945 m/s and ? = 2.46 10-6 radians/s. What is the average acceleration of the Moon over the following time intervals? For each, give the magnitude and direction as an angle measured counterclockwise from the positive x-axis. t=0 to t= 0.500 days t=0 to t=0.0050days

Explanation / Answer

at t=0.5 days Vx = -945*sin(2.46*10^-6*43200) = -100.23811

//y Vy = 945*cos(2.46*10^-6*43200) = 939.6687

Vt1 = -100.24i + 939.67j

V0 = 0 + 945j

Average acceleration =(Vt1 - V0)/t

a1 = (-100.24i -5.33j)/43200 = -(23.20i + 1.23j)*10^-4

|a1| = 23.23*10^-4

Doing similar calculations

a2 = -23.24i -0.00124j

|a2|= 23.24m/s^2

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.