The Moon orbits the Earth every 27.3 days and has an averagedistance from the ce

Question

The Moon orbits the Earth every 27.3 days and has an averagedistance from the center of the Earth of 3.9 X 105 km.Calculate the time it takes a satellite averaging 6.7 X103 km above the Earth to complete one orbit. Please use Kepler's third law mathematical formula. Thankyou. The Moon orbits the Earth every 27.3 days and has an averagedistance from the center of the Earth of 3.9 X 105 km.Calculate the time it takes a satellite averaging 6.7 X103 km above the Earth to complete one orbit. Please use Kepler's third law mathematical formula. Thankyou.

Explanation / Answer

      Time period of moon, T1 = 27.3 days        Time period ofsatellite, T 2 = ?       distance of moon fromcenter of earth, R 1 = 3.9 X 105 km        height of satelliteabove the earth, h = 6.7 X 103 km        radius of earth, R = 6400km = 6.4 X 10 3 km        distance ofsatellite from center of earth, R2 = R + h= 13.1 X 10 3 km = 0.131 X 10 5km           Fromkepler's third law,   T 2    R 3                                     (T 2 / T 1) 2 = (R2 / R1) 3       plug in the values to getthe answer for T 2       plug in the values to getthe answer for T 2

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