The batteries shown in the circuit in the figure ( Figure 1 ) have negligibly sm

Question

The batteries shown in the circuit in the figure (Figure 1)have negligibly small internal resistances. Assume that E = 9.00V and R = 18.6? .

Find the current through the 30.0 ? resistor?

Find the current through the 18.6? resistor.

Find the current through the 9.00V battery.

The batteries shown in the circuit in the figure (Figure 1)have negligibly small internal resistances. Assume that E = 9.00V and R = 18.6? . Find the current through the 30.0 ? resistor? Find the current through the 18.6? resistor. Find the current through the 9.00V battery.

Explanation / Answer

let the potential along bottom line is 0

hence potential along top line will be 9 v

hence

current through 30 resistor = I = V/R = 9/30 = 0.3 A

voltage across 18.6 resistor is 9-5 = 4

hence

current through 18.6 resistor = I = V/R = 4/18.6 = 0.22 A

current through 9 V battery = 0.3 + 0.22 = 0.52 A

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