A 0.01 microF air-filled capacitor is connected across a 120-V voltage source. a

Question

A 0.01 microF air-filled capacitor is connected across a 120-V voltage source.

a) If the air gap between the two plates is 0.1 mm, what is the area A of the plates?

b) After the voltage source fully charges the capacitor, the capacitor is immersed in transformer oil (of dielectric constant 4.5). What is the change of the electric charge deltaQ in the capacitor if the voltage source remained connected during the process.

c) What is the change of the electric energy deltaU in the capacitor if the voltage source is disconnected from the capacitor after charging and then the capacitor is immersed in oil?

Explanation / Answer

a) C = A*epsilon/d

A = c*d/epsilon = 0.113 m^2

b) Q = k*c*v = 5.4 *10^-6C

c) U = 0.5*c*v^2 = 72*10^-6

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.