A .28 kg block is suspended from the middle of a 1.98 m long string (099m segmen

Question

A .28 kg block is suspended from the middle of a 1.98 m long string (099m segments). The ends of the string are attached to the ceiling at points separated by 1 m, and the block can slip along the long string.

The acceleration of gravity is 9.81 m/s2.

1. What angle does the string make with the ceiling?
Answer in units of degrees.
2. What is the tension in the string?
Answer in units of N.

3. The .28 kg block is removed and two .14 kg blocks are attached to the string such that the three string segments are equal (.66m each). What is the tension in the string segments attached to the ceiling on the right?
Answer in units of N.

4. What is the tension in the horizontal segment?
Answer in units of N.

I already solved for the angle and I got 59.67 degrees.
I tried solving for the tension on the string but got confused, if you could show me the steps to finding it that would be great! :)

Explanation / Answer

Number 1 you have right number 2 upward force = 2 . T sin 51.88° ( "2" because there are two strings pulling up. ) 1.573 T = m . g = 0.66 . 9.8 T = 4.11 N now I have to go ... good luck with the rest ;-) Source(s): Old teacher

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