Ls4203_class test_2017 please answer only question no.1. (5marks) Y How many mol
ID: 213139 • Letter: L
Question
Ls4203_class test_2017
please answer only question no.1. (5marks)
Explanation / Answer
The Given structure is Oleic acid consist 18 carbons with 1 double bond at 9. Now for the activation of oleate to oleoyl Co-A the energetic cost is equivalent to 2 ATP. This Oleoyl Co-A will enter into the Beta Oxidation.
Beta Oxidation
To the del position 9, there will be three beta oxidation reaction and will produce 3 acetyl Co-A and cis del3 Dodecenoyl Co-A. After that an isomerase, isomerises the position of double bond from 3 to 2. So, there will be 5 more beta oxidation reaction and will produce 6 acetyl Co-A.
There will be total 8 beta oxidation and 9 acetyl Co-A will be produced.
8 beta oxidation will produce 30.5 ATP. (due to double bond at 9 acyl Co-A dehydrogenase will be skipped and 1 FADH2 will not be produced.)
1 NADH = 2.5 ATP
1 FADH2= 1.5 ATP
Now these produced 9 acetyl Co-A will enter TCA cycle. 1 TCA cycle will produce 3 NADH, 1FADH2, 1 GTP. So, for 9 acetyl Co-A will produce 27 NADH, 9 FADH2, 9 GTP entering into Oxidative phosphorylation (ETC) will produce 90 ATP.
Now the total production of ATP will be
30.5 + 90 – 2 = 118.5 ATP
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