Trying to understand the concepts behind these problems. Please help!! 1) An 65

Question

Trying to understand the concepts behind these problems. Please help!!

1) An 65 kg skier is sliding down a ski slope at a constant velocity. The slope makes an angle of 24° above the horizontal direction. What is the coefficient of kinetic friction between the skis and the snow?

2) A box sits on a horizontal wooden board. The coefficient of static friction between the box and the board is 0.29. You grab one end of the board and lift it up, keeping the other end of the board on the ground. What is the angle between the board and the horizontal direction when the box begins to slide down the board?

3) Two boxes with different masses M1 = 2.0 kg and M2 = 2.1 kg are tied together on a frictionless ramp surface which makes an angle = 25° with the horizontal (see the figure below).

What is the tension in the rope connecting the two boxes?
N

What is the tension in the rope connecting the first box to the ramp?
N

Please show work (equations and math) and explanation of why? THANK YOU!!

An 65 kg skier is sliding down a ski slope at a constant velocity. The slope makes an angle of 24 degree above the horizontal direction. What is the coefficient of kinetic friction between the skis and the snow? A box sits on a horizontal wooden board. The coefficient of static friction between the box and the board is 0.29. You grab one end of the board and lift it up, keeping the other end of the board on the ground. What is the angle between the board and the horizontal direction when the box begins to slide down the board? Two boxes with different masses M1 = 2.0 kg and M2 = 2.1 kg are tied together on a frictionless ramp surface which makes an angle = 25 degree with the horizontal (see the figure below). What is the tension in the rope connecting the two boxes? N What is the tension in the rope connecting the first box to the ramp? N

Explanation / Answer

1) f = u*mg*cos24 = m*g*sin24

u = tan24 =0.445
2)u = tan(theta) =======>theta =tan^-1(u) = 16.17 degrees

3) a) T = M2*g*sin25 = 8.69 N
b) T = M1+M2)*g*sin25 = 16.98 N

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