Trying to find the solution to the third part of this question: For what value o

Question

Trying to find the solution to the third part of this question: For what value of z does T achieve its minimum value? I cannot seem to get this answer right. Please help!

Quadratic Equation roots for the following equation. Cle, two There are two roots for the following equation. (i.e., two values of z for which T equals zero.) T = 2.5z2 + 20.83z + 0.60 Calculate the more positive of the two. -2.89x1o-2 You are correct. Your receipt no. is 156-2917/ What is the other root of this equation? -8.30 You are correct. Your receipt no. is 156-7392 For what value of z does T achieve its minimum value? 0.0289 The extremum is located in the middle between the two roots. --. Submit Answer Incorrect. Tries 2/10 Previous Tries © 1998-2016 by Florida State University. All rights reserved The contents of this web site are for use by the students enrolled in this course only. Any distribution of the contents in whole or in par version, is a violation of the Copyright laws and the FSU honor codes. This discussion is closed.

Explanation / Answer

T : 2.5z^2 + 20.83z + 0.60

2.5z^2 + 20.83z + 0.60 =0

solve the quadratic : z =( -20.83 +/- sqrt( 20.83^2 -4*0.60*2.5)/2*2.5

z1 = -0.0289 = -2.89 x 10^-2 (more +ve root)

; z2 = -8.303 = -8.303 x 10^-2 (other root)

Minimum value of T occurs at vertex of quadratic eqution

az^2 +bz +c ; Minimum occurs at z = -b/2a

z = -20.83/(2*2.5) = -4.166

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