Two capacitors, C 1 = 1.0 m F and C 2 = 9.0 m F , are in series. Can someone ple

Question

Two capacitors, C1 = 1.0mF and C2 = 9.0mF , are in series. Can someone please explain part d and what is the answer. Thank you.
A. Find the equivalent capacitance. c=.90mF B.If the combination is connected across a 16v Battery  find the charge stored on the first capacitor. 1.4*10^-2C C.Find the potential difference across first capacitor. 14V D. Find the charge stored on the second capacitor. ? E. Find the potential difference across second capacitor. 1.6V Two capacitors, C1 = 1.0mF and C2 = 9.0mF , are in series. Can someone please explain part d and what is the answer. Thank you.
A. Find the equivalent capacitance. c=.90mF B.If the combination is connected across a 16v Battery  find the charge stored on the first capacitor. 1.4*10^-2C C.Find the potential difference across first capacitor. 14V D. Find the charge stored on the second capacitor. ? E. Find the potential difference across second capacitor. 1.6V Two capacitors, C1 = 1.0mF and C2 = 9.0mF , are in series. Can someone please explain part d and what is the answer. Thank you.
A. Find the equivalent capacitance. c=.90mF B.If the combination is connected across a 16v Battery  find the charge stored on the first capacitor. 1.4*10^-2C Two capacitors, C1 = 1.0mF and C2 = 9.0mF , are in series. Can someone please explain part d and what is the answer. Thank you.
A. Find the equivalent capacitance. c=.90mF B.If the combination is connected across a 16v Battery  find the charge stored on the first capacitor. 1.4*10^-2C C.Find the potential difference across first capacitor. 14V D. Find the charge stored on the second capacitor. ? E. Find the potential difference across second capacitor. 1.6V

Explanation / Answer

d)

q1 = 1.44e-2 C

V1 = q1/C1 = 1.44e-2/1e-3 = 14.4 V

V_2 = V - V1 = 16 - 14.4 = 1.6 V

q_2 = C_2 V_2 = 9e-3 * 1.6 = 1.4 x 10^-2 C

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