Two capacitors C1 = 10 µF and C2 = 20 µF are connected to a battery using the sw
ID: 2050498 • Letter: T
Question
Two capacitors C1 = 10 µF and C2 = 20 µF are connected to a battery using the switch S. When the switch is in position A the capacitor C1 is connected to a VB = 12 Volt battery. When the switch is moved to position B the capacitor C1 is disconnected from the battery but remains with the same charge when it was connected to the battery. When the switch is moved to position C the charged capacitor C1 is connected to the uncharged capacitor C2.
(a) When the switch is in position B, what is the charge on the capacitor C1? µC
(b) When the switch is in position C (after stabilizing), what is the charge on capacitor C1?
µC
(c) When the switch is in position C (after stabilizing), what is the voltage across capacitor C1?
V
(d) When the switch is in position C (after stabilizing), what is the charge on capacitor C2?
µC
(e) When the switch is in position C (after stabilizing), what is the voltage across capacitor C2?
V
Explanation / Answer
(a)q = CV = 10*12 = 120 µC
(b) When shifted to position C, total charge remains same
q1 + q2 = 120
Voltage across C1 = C2
q1/C1 = q2/C2
q1/10 = q2/20
q2 = 2*q1
q1 = 40 µC
q2 = 80 µC
V1 = q1/c1 = 4V
V2 = q2/C2 = 4V
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