A shot-putter throws the shot ( mass = 7.3 kg) with an initial speed of 14.0 m/s

Question

A shot-putter throws the shot ( mass = 7.3 kg) with an initial speed of 14.0 m/s at a 34.0 degree angle to the horizontal. Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.10 m above the ground. A shot-putter throws the shot ( mass = 7.3 kg) with an initial speed of 14.0 m/s at a 34.0 degree angle to the horizontal. Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.10 m above the ground. Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.10 m above the ground.

Explanation / Answer

Ux=14 cos34

Uy=14 sin34

-2.1=14sin34*t-1/2*9.8*t^2 [upward is positive y axis)

-2.1=7.8t-4.9t^2

=>4.9t^2-7.8t-2.1=0

=>t=1.83s

Horizontal distance=14cos34*1.83=21.24 m

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