A shot-putter throws the shot with an initial speed of 11.2m/s from a height of

Question

A shot-putter throws the shot with an initial speed of 11.2m/s from a height of 5.00 feet above the ground. What is therange of the shot if the launch angle is 20 degrees? I calculated 8.219 m on the 5 foot plane however, I cannotfigure out a way to calculate the additional range cause by theshot-put dropping the additional 5 feet. Please help. Thanks A shot-putter throws the shot with an initial speed of 11.2m/s from a height of 5.00 feet above the ground. What is therange of the shot if the launch angle is 20 degrees? I calculated 8.219 m on the 5 foot plane however, I cannotfigure out a way to calculate the additional range cause by theshot-put dropping the additional 5 feet. Please help. Thanks

Explanation / Answer

Height H = 5 ft               = 5 * 0.3 m               = 1.5 m Time taken to reach the groud be   t then fromthe relation , S = ut + ( 1/ 2) at 2 we find t value where u = initial velocity = v sin            a= 9.8 m / s 2            v= speed = 11.2 m / s            = 20 o substitue values weget   t value So, horizonatl range = v cos * t substitue values weget answer substitue values weget   t value So, horizonatl range = v cos * t substitue values weget answer

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