A proton accelerates from rest in a uniform electric field of 650 N/C. At one la

Question

A proton accelerates from rest in a uniform electric field of 650 N/C. At one later moment, its speed is 1.10 Mm/s (nonrelativistic because v is much less than the speed of light).

                                                               

A proton accelerates from rest in a uniform electric field of 650 N/C. At one later moment, its speed is 1.10 Mm/s (nonrelativistic because v is much less than the speed of light). Find the acceleration of the proton. Over what time interval does the proton reach this speed? How far does it move in this time interval? What is its kinetic energy at the end of this interval?

Explanation / Answer

a) q*E = m*a

==> a = q*E/m = 1.6*10^-19*650/1.67*10^-27 = 6.23*10^10 m/s^2

b)v = 0 + a*t

t = v/a = 1.1*10^6/6.23*10^10 = 1.76*10^-5 s

c) s = 0.5*a*t^2 = 9.65 m

d)Ke = 0.5*m*v^2 = 1.01*10^-15 J

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