Three point charges have equal magnitudes, two being positive and one negative.
ID: 2124822 • Letter: T
Question
Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equilateral triangle, as the drawing shows. The magnitude of each of the charges is 2.9
Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equilateral triangle, as the drawing shows. The magnitude of each of the charges is 2.9 mu C, and the lengths of the sides of the triangle are 4.0 cm. Calculate the magnitude of the net force that each charge experiences.Explanation / Answer
the magnitude of the electric force between any two charges is
/F = kq^2 /a^2 = 9*2.9^2*10^-12/0.04*0.04 = 47.346 N
There are two F for each charge. If the angle between these two F is ?, the magnitude of resultant force is
sqrt(F^2 + F^2 + 2F^2cos?) = ?sqrtF^2(1 + cos?)] = 2Fcos(?/2)
a) For A, ? = 60o, so FA = 2Fcos(30)= = 81.9 N
b) For B, ? = 120o, so FB = 2Fcos(60) = 47.346 N
c) For C, ? = 120o, so FC = 2Fcos(60) =47.346 N
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.