1. An ethernet cable is 3.90 m long and has a mass of 0.190 kg. A transverse pul
ID: 2122736 • Letter: 1
Question
1.
An ethernet cable is 3.90 m long and has a mass of 0.190 kg. A transverse pulse is produced by plucking one end of the taut cable. The pulse makes four trips down and back along the cable in 0.855 s. What is the tension in the cable?
2. A 500-g block is released from rest and slides down a frictionless track that begins 1.50 m above the horizontal, as shown in the figure below. At the bottom of the track, where the surface is horizontal, the block strikes and sticks to a light spring with a spring constant of 15.0 N/m. Find the maximum distance the spring is compressed.
3. An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large object suspended from it. Assume a wire of mass 3.60 g is 1.60 m long and has a 3.00-kg object suspended from it. A pulse requires 48.5 ms to traverse the length of the wire. Calculate gplanet from these data. (You may neglect the mass of the wire when calculating the tension in it.)
Question Part Points Submissions UsedExplanation / Answer
Number 1
Apply v = sqrt(T/u)
v = d/t = 8(3.90)/(.855) = 36.5 m/s
36.5 = sqrt(3.9T/.19)
T = 64.9 N
Number 2)
PE = EPE
mgh = .5kx^2
(.5)(9.8)(1.5) = (.5)(15)(x^2)
x = .99 m (99 cm)
Number 3)
v = sqrt(T/u)
T = mg and d = vt
(1.6)/(48.5 X 10^-3) = sqrt[(3)(g)(1.6)/(3.6 X 10^-3)]
g = .816 m/s^2
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