The left end of a long glass rod 7.00 c m in diameter has a convex hemispherical
ID: 2122020 • Letter: T
Question
The left end of a long glass rod 7.00cm in diameter has a convex hemispherical surface 3.50cm in radius. The refractive index of the glass is 1.60. The glass rod is immersed in oil (n=1.45). An object placed to the left of the rod on the rod's axis is to be imaged 1.25m inside the rod. Part A How far from the left end of the rod must the object be located to form the image? ANSWER: s= ? The left end of a long glass rod 7.00cm in diameter has a convex hemispherical surface 3.50cm in radius. The refractive index of the glass is 1.60. The glass rod is immersed in oil (n=1.45). An object placed to the left of the rod on the rod's axis is to be imaged 1.25m inside the rod. The left end of a long glass rod 7.00cm in diameter has a convex hemispherical surface 3.50cm in radius. The refractive index of the glass is 1.60. The glass rod is immersed in oil (n=1.45). An object placed to the left of the rod on the rod's axis is to be imaged 1.25m inside the rod. The left end of a long glass rod 7.00cm in diameter has a convex hemispherical surface 3.50cm in radius. The refractive index of the glass is 1.60. The glass rod is immersed in oil (n=1.45). An object placed to the left of the rod on the rod's axis is to be imaged 1.25m inside the rod. Part A How far from the left end of the rod must the object be located to form the image? ANSWER: s= ? Part A How far from the left end of the rod must the object be located to form the image? ANSWER: s= ? Part A How far from the left end of the rod must the object be located to form the image? ANSWER: s= ? ANSWER: s= ?Explanation / Answer
Apply n1/p + n2/q = (n2-n1)/R
1.45/p + 1.6/1.25 = (1.6 - 1.45)/.035
p = .482 m (48.2 cm)
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.