Full points goes to the person who shows the calculations. A man of mass 60 kg f

Question

Full points goes to the person who shows the calculations.

A man of mass 60 kg falls from rest and slides down a ski-slope (without his skis) as shown (diagram not to scale). At point P, at which he has fallen a vertical height H meters as shown, his speed is vo = 10 m/s. Assume he slides without any frictional force or air resistance acting on him until he reaches point P. Calculate the value of H After point P, air resistance and friction cannot be ignored and have a significant effect on his subsequent motion. If 720 J of his mechanical energy at P are transformed into heat as he slides from P to Q, with what speed does he arrive at Q (note that this does NOT depend on your answer to part (i))?

Explanation / Answer

Part 1)

mgH = .5mv^2

(9.8)(H) = (.5)(10^2)

H = 5.10 m

Part 2)

The KE - Enegry Lost - PE going back up will equal KE back at Q

(.5)(60)(10^2) - 720 - (60)(9.8)(3) = .5(60)(v^2)

v = 4.15 m/s

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