Full points for full answers What is the free air volume flow rate required for

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Full points for full answers

What is the free air volume flow rate required for a single acting cylinder if the system gauge pressure is 5 bar, the piston has a diameter of 80 mm, stroke length is 400 mm and cylinder does 10 strokes per minute.

Assume Ambient pressure 101 kPa.

A double-acting cylinder has a piston diameter of 50 mm. The piston rod 25 mm in diameter and pressure is supplied  at 4 MPa. What is the force produced by the cylinder for extension and retraction if the efficiency of the system is 95%.

A double-acting cylinder has a piston diameter of 25 mm. The piston rod is 5 mm in diameter and pressure is supplied at 3.5 MPa. Calculate force produced by the cylinder during extension and retraction.

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A double-acting cylinder has a piston with a diameter of 50 nun. The piston rod is 25 mm in diameter and pressure is supplied to the system at 4 MPa. Calculate the force produced by the cylinder for extension and retraction if the efficiency of the system is 95%. Determine the free air volume flow rate required for a single acting cylinder if the system gauge pressure is 5 bar: the piston has a diameter of 80 mm: the stroke length is 400 mm and the cylinder completes 10 strokes per minute. Take the ambient pressure to be 101 kPa.

Explanation / Answer

1)

gauge pressure = 5 bar = 500 Kpa = 72.5 psig

diameter of piston = 80mm = 3.149 inches

area = pi*d^2 /4

Converting the flow rate from CFM (compressed air) to SCFM (free air) can be calculated as follows:

2)

For the retracting stroke on a double acting cylinder:

FR = pi * (D^2 - d^2)/4 x P x mew

Where:

FR represents the cylinder thrust to retract

D = piston diameter = 25 mm

d = piston rod diameter = 5 mm

P = available pressure = 3.5 MPa = 3.5*10^6 N/m^2

mew = efficiency = 0.95

force produced by the cylinder for retraction = 3.14 *3.5*10^6 ((25^2-5^2)/4)*10^-6 * 0.95 = 6264.3 N

force produced by cylinder for extension = pi*D^2 *P*mew = 3.14*25^2 *10^-6 *3.5*10^6 *0.95 = 6525.31 N

3)

For the retracting stroke on a double acting cylinder:

FR = pi * (D^2 - d^2)/4 x P x mew

Where:

FR represents the cylinder thrust to retract

D = piston diameter = 50 mm

d = piston rod diameter = 25 mm

P = available pressure = 4 MPa = 4*10^6 N/m^2

mew = efficiency = 0.95

force produced by the cylinder for retraction = 3.14 *4*10^6 ((50^2 - 25^2)/4)*10^-6 * 0.95 = 22372.5 N

force produced by cylinder for extension = pi*D^2 *P*mew = 3.14*50^2 *10^-6 *4*10^6 *0.95 = 29830 N

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