1. A proton is confined to the nucleus of an atom. Assume the nucleus has diamet

Question

1. A proton is confined to the nucleus of an atom. Assume the nucleus has diameter 5.5 x 10^-15 m and that this distance is the uncertainty in the proton's position. What is the minimum uncertainty in the momentum of the proton?

Delta pmin =

2. An electron is confined in an atom. Assume the atom has diameter 1 x 10^-10 m and that this distance is the uncertainty in the electron's position. What is the minimum uncertainty in the momentum of the electron?

Dealt pmin =

I've tried so many times with equation delta p = h/(2*pi*diameter), but I can't get the answer.

Can somebody please walk me through this problem step by step? Thanks

Explanation / Answer

1) delta_p * delat_x = %u0127/2

     delta_p *5.5*10^-15= (1.055*10^-34 J-s)/2

delta_p = 0.095*10^-19

2) delat_p = 0.527*10^-24

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