I have been working on this question and cannot get it right, I only have 2 atte

Question

I have been working on this question and cannot get it right, I only have 2 attempts left!! If someone could show me how to work through this that would be great.

A tube has a length of 0.036 m and a cross-sectional area of 5.5 x 10-4 m2. The tube is filled with a solution of sucrose in water. The diffusion constant of sucrose in water is 5.0 x 10-10 m2/s. A difference in concentration of 5.7 x 10-3 kg/m3 is maintained between the ends of the tube. How much time is required for 2.1 x 10-13 kg of sucrose to be transported through the tube?

Explanation / Answer

Ficks law of diffusion......

J=-D*dC/dx

J=5*10^-10*5.7*10^-3/.036

(2.1*10^-13/.342)/(5.5*10^-4 * T )=5*10^-10*5.7*10^-3/.036

T=(2.1*10^-13/.342)/(5.5*10^-4)/(5*10^-10*5.7*10^-3/.036)

T=14.102

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