1) Mr. Goldfinger breaks into Ft. Knox to steal the gold. Each gold brick has di
ID: 2119799 • Letter: 1
Question
1) Mr. Goldfinger breaks into Ft. Knox to steal the gold. Each gold brick has dimensions of 3 cm by 2.7 cm by 13 cm. Goldfinger can only escape carrying an additional weight of 230 N (50.6 pounds). What is the maximum number of bricks that he could escape with? Gold is being exchanged at a rate of $50 (USD) per gram. What is the dollar value of Goldfinger's stolen gold? 2) What is the approximate mass of air in a living room 4.70 m*3.70 m*2.58 m? 3) The maximum gauge pressure in a hydraulic lift is 17.3 atm. What is the largest size vehicle (in kg) it can lift if the diameter of the output line is 26.0 cm? 4) What is the absolute pressure on the bottom of a swimming pool 18.6 m by 9.60 m whose uniform depth is 1.84 m? What is the total force on the bottom of that swimming pool? What will be the pressure against the side of the pool near the bottom? 5) Determine the minimum gauge pressure needed in the water pipe leading into a building if water is to come out of a faucet on the twelfth floor, 37.8 m above that pipeExplanation / Answer
Q1 ... volume of 1 brick = 3 * 2.7 * 13 = 105.3 cm^3 density of gold = 19.3 g / cm^3 so mass of 1 brick = volume * density = 105.3 * 19.3 = 2032.29 grams = 2.03229 kg given .. weight = 230 N = 230/9.8 = 23.4694 kg.. so number of bricks = (total mass ) / ( mass of 1 brick) = 23.4694/ 2.03229 = 11.548 bricks.. so he can carry 11 bricks .. dollar value = mass (in grams ) * $ 50 = 23.4694 * 1000 * 50 =$ 1173470 2) volume = 4.7 * 3.7 * 2.58 = 44.8662 m^3 density of air = 1.1839 kg / m^3 so mass of air = density * volume = 1.1839 * 44.8662 = 53.117 kg 3) pressure = 17.3 atm = 17.3 * 101325 Pa = 1752922.5 pa so mass of vehicle = (pressue * area ) / (9.8 ) = ( 1752922.5 * pi * 0.13^2 ) / 9.8 = 9496.711 kg 4) absolute pressure = atmospheric pressure + pressure due to depht = 101325 + ( density * g * depth ) = 101325 + ( 1000 * 9.8 * 1.84) = 119357 Pa force = pressure * area = 119357 * 18.6 * 9.6 = 21312385.92 N pressure at teh side near the base = pressure at the base = 119357 Pa 5) minimum gauge pressure = density * g * height = 1000 * 9.8 * 37.8 = 370440 Pa
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