P56 tor Canvas Word HILE HOME INSER DESIGN PAGE LAYOUT REHERENYES MAILINGS REVIE
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P56 tor Canvas Word HILE HOME INSER DESIGN PAGE LAYOUT REHERENYES MAILINGS REVIEWVIEW Nathan Rut:a Question 4 (5 points). Consider 3 gene loci in the pea plant. Locus 1 affects seed color; allele G for green, g for yellow. Locus 2 affects seed shape; allele R for round, r for wrinkled. Locus 3 affects flower color; allele B for red, b far white. Each upper case allele is oompletely dominant to thelr corresponding lower case, recesslve allele. Each locus is on a different non-honolagous chromosomeso,the loci segregate or sort independenty from each other during meiosis. Two parent pea plants, each of genotype GgBrBD, are mated with each other. That mating produced 1000 progeny a. What fraction af the gametes of the parents are expected to contain only recessive alleles? b. How many phenotypic classes are cxpected among the progeny? c. What fraction af the progeny are expected to have the combination green seed, round seed, and red flowers? d. How many progeny are expected to have the combination yellow seed, wrinkled seed, and white flowers? e. How many genotypic classes are expected among the progeny? SHOW ALL YOUR CALCULATIONS 5:27 PM O Type here to searchExplanation / Answer
Parental cross: GgRrBb X GgRrBb
Number of different types of gametes produced by each parent = 2 X 2 X 2 = 8
The probability of producing grb gamete by each parent = 1/8
Here, number of genes n = 3
Formula for calculating number of phenotypic classes = 2^n
= 2^3 = 2 X 2 X 2 = 8
Formula for calculating number of phenotypic classes = 3^n
= 3^3 = 3 X 3 X 3 = 27
The fraction of progeny with Green seed, round seed and red flowers (G_R_B_) = 3/4 X 3/4 X 3/4 = 27/64
The fraction of progeny with yellow seed, wrinkled seed and white flowers (ggrrbb) = 1/64
Trihybrid cross:
Genotypic ratio = 1:1:1:1:1:1:1:1:2:2:2:2:2:2:2:2:2:2:2:2:4:4:4:4:4:4:8
Phenotypic ratio = 27:9:9:9:3:3:3:1
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