Long, long ago, on a planet far, far away, a physics experiment was carried out.

Question

Long, long ago, on a planet far, far away, a physics experiment was carried out. First, a 0.210-kg ball with zero net charge was dropped from rest at a height of 1.00 m. The ball landed 0.450s later. Next, the ball was given a net charge of 7.80%u03BCC and dropped in the same way from the same height. This time the ball fell for 0.645s before landing.

Part A

What is the electric potential at a height of 1.00 m above the ground on this planet, given that the electric potential at ground level is zero?

Please answer in V

Explanation / Answer

let acceleration of gravity be g

whe there is electrostatic force

1/2*g*t^2=h

g=2h/t^2=2*1/0.45^2=9.87m/s2

for second case

a=2h/t^2=2*1/0.645^2=4.8m/s2

tjis difference in acceleration is attributed to electrostatic force

m(a-g)=qE

E=m(a-g)/q=-0.21*(9.87-4.8)/(7.8*10^-6)=-136500V/m

V=-EL=-136500*1= -136500V

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