An air bubble of 10 cm^3 is created at bottom of a lake, where the temperature i

Question

An air bubble of 10 cm^3 is created at bottom of a lake, where the temperature is 5 degree celsius and is 100 m deep.

a)What is the pressure at the bottom

b)What is the bouancy force exerted on the air bubble?

c)As the air bubble rises towards the surface of the lake where the temperature is 30 degree celsius the volum becomes larger and larger, what is the volume of the bubble just before it reaches the surface of ther lake. denisty of water is p=1,000 kg/m^3 and atmospheric pressure is Pa=1.103 x 10^5 N/m^2

Explanation / Answer

1)pressure at the bottom=Po+rho*g*h

=10^5+1000*9..8*100

=10.8*10^5 N/m^2

=10.8 atm

b)bouant force=rho*V*g

=1000*9.8*10*10^-6

=0.098 N

c)since the number of moles of the gas in the bubble is constant .so,

using PV/T =constant.so,

10^5*V/303=10.8*10^5*10/278

or V=117.712 cm^3

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