An air bubble of 25 cm 3 volume is at the bottom of alake 50 m deep where the te

Question

An air bubble of 25 cm3 volume is at the bottom of alake 50 m deep where the temperature is 4.0°C. The bubble risesto the surface, which is at a temperature of 17.6°C. Take thetemperature of the bubble's air to be the same as that of thesurrounding water. Just as the bubble reaches the surface, what isits volume, in cubic cm?

Explanation / Answer

Using ideal gas law: PV = nRT => PV / T = nR = constant so P1V1 / T1 =P2V2 / T2 [(101325 Pa) + (50 m)(1000 kg/m3) (9.8 m/s2)(25 cm3)] / (277 K) = [(101325 Pa) (V2)] /(290.6 K) V2 = 127.88cm3 Note: I used Google's calculator, so the final answer maybe off, but the work is correct.

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