A 5.0-kg block and a 4.0-kg block are connected by a 0.6-kg rod. The links betwe

Question

A 5.0-kg block and a 4.0-kg block are connected by a 0.6-kg rod. The links between the blocks and the rod are denoted by A and B. A force F is applied to the upper block.

In Fig. 4.3, the blocks and rod assembly moves downward at constant velocity. The applied force F is closest to:

In Fig. 4.3, the blocks and rod assembly moves upward at constant velocity. The force in link A is closest to:

In Fig. 4.3, the force in link B is 40 N. The acceleration of the blocks and rod assembly, including direction, is closest to:

Explanation / Answer

1) 9.6*9.8 = 94 N

2) The force in link A = 94 - 5*9.8 = 45

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