A 5.0 kg block is pushed 8.0 m up a rough 36° inclinedplane by a horizontal forc

Question

A 5.0 kg block is pushed 8.0 m up a rough 36° inclinedplane by a horizontal force of 79 N. If the initial speed of theblock is 2.4 m/s up the plane and a constant kinetic friction forceof 24 N opposes the motion, calculate the following. (1) the work done by the frictional force (2) the final kinetic energy of the block A 5.0 kg block is pushed 8.0 m up a rough 36° inclinedplane by a horizontal force of 79 N. If the initial speed of theblock is 2.4 m/s up the plane and a constant kinetic friction forceof 24 N opposes the motion, calculate the following. (1) the work done by the frictional force (2) the final kinetic energy of the block

Explanation / Answer

mass m = 5 kg distance S = 8 m angle = 36 degrees horizontal force F = 79 N Initial speed u = 2.4 m / s kinetic frcitinal force   f = 24 N ( 1) . work done by frictional force W = f S = 192J (2). final kinetic energy K ' = ? work done by external force W ' = F cos   * S                                                   = 511.29 J work done by gravity = mg cos * S                             W"  = 317.13 J net work done w = W ' - W - W "                           = 2.155 J we know net work = change in kinetic energy                         w = K - K ' final kinetic energy K ' = K -w where K = initial kinetic energy = ( 1/ 2) m u ^2               = 14.4 So, K ' = 12.24 J

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