A horizontal disk of rotational inertia 2 4.25kgm^2 with respect to its axis of

Question

A horizontal disk of rotational inertia 2 4.25kgm^2 with respect to its axis of symmetry is

spinning counterclockwise about its axis of symmetry, as viewed from above, at

15.5 revolutions per second on a frictionless massless bearing. A second disk, of rotational

inertia 2 1.80 kgm^2 with respect to its axis of symmetry, spinning clockwise as viewed from

above about the same axis (which is also its axis of symmetry) at 14.2 revolutions per second, is dropped on top of the first disk. The two disks stick together and rotate as one about their common axis of symmetry at what new angular velocity (in units of radians per second)?

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Explanation / Answer

Here the Angular momentum remains Constant

Therefore

24.25*15.5 - 21.80*14.2 = (24.25+21.80)*w

Here i Take Counterclockwise positive.

Therefore

w = 1.44007 rev/sec

= (1.44007*2pi)rad/sec

= 9.048 rad/sec

As the answer is positive so Counterclockwise

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