Two blocks move along a linear path on a nearly frictionless air track. One bloc

Question

Two blocks move along a linear path on a nearly frictionless air track. One block, of mass 0.118 kg, initially moves to the right at a speed of 4.90 m/s, while the second block, of mass 0.236kg, is initially to the left of the first block and moving to the right at 7.40 m/s. Find the final velocities of the blocks, assuming the collision is elastic.

velocity of the 0.118 kg block = ---Select---to the rightto the leftno direction velocity of the 0.236 kg block = ---Select---to the rightto the leftno direction

Explanation / Answer

final velocity for elastic colliosin is given by :

v1 = [u1 * ( m1 - m2 ) + 2*m2 * u2 ] / (m1 + m2 )

u1 = initial velosity of block 1 = 4.9 m/sec

m1= mass of block 1 = 0.118 kg

u2 = 7.4

m2 = 0.236 kg

so v1 = ( 4.9 * ( 0.118 - 0.236 ) + 2*7.4*0.236 )) / ( 0.118 + 0.236 ) = 8.23333 m/sec

so final velocity of 0.118 = 8.23 m/sec to the right

v2 = ( 7.4 * ( 0.236 - 0.118 ) + 2*4.9*0.118 )) / ( 0.118 + 0.236 ) = 5.73 m/sec to the right

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