(a) Calculate the power dissipated by the battery in the following circuit. (b)

Question

(a) Calculate the power dissipated by the battery in the following circuit. (b) If the 5.0-ohms resistor represents a crane lifting a 1.0-kg mass with 25% efficiency, how long would the circuit have to run to lift the mass to the top of the Empire State building? (c) How long would the circuit have run to lift the 1.0-kg mass to a height twice the radius of the earth, assuming the same 25% efficiency? (Hint: for part (b) you can use the near earth approximation to the potential energy of gravity, in part (c) you cannot)

https://media.cheggcdn.com/media%2F0f4%2F0f42a5d1-e9e9-4023-b948-0c3dd97d5d31%2FphpHqTBnc.png

Please show work using equations and steps please!

Explanation / Answer

power dissipated = V*I

Equivalent resistance = 6 ohms

Current = V/R = 2 A

power disspiated = 12 W

(B) Height of Empire State Building = 443m

Work done = mgh/efficiency = 1*9.81*443/0.25 = 17383 W

Current in the 5 ohm resistor = (3/9)*2 = 2/3 A

Power Dissipated = I^2 * R * t = 17383

=> time, t = 7822.35 seconds

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