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4. The circuit is returned to its original state. A fourth bulb (D) is connected

ID: 2112693 • Letter: 4

Question


4. The circuit is returned to its original state. A fourth bulb (D) is connected in parallel with bulb B (not in parallel with B and C). (Sketch the bulb on the circuit.)

http://www4.wittenberg.edu/academics/phys/pvoytas/p21806/labs/lab8_ohms/hw_3_997.pdf
(copy and paste to view circuit)

A. What happens to the brightness of each of the three bulbs

B. What happens simultaneously to the current through point 3?

C. What happens simultaneously to the potential difference between points 3 and 4?

D. What happens simultaneously to the potential difference between points 4 and 2?

5. State Ohm's law in words. For what type of circuit elements does it correctly

Explanation / Answer

ANSWER You really need more information to get a true answer. One will have to make several assumptions (dangerous) to come up with a realistic answer. First is the battery: It is 1.5 volts, but its output capacity (current) is not given. If this is to be a practical circuit one must believe that the current is adequate to light all lamps properly. For that purpose I will assume that lamp 'A' is a 1.5 volt lamp and lamps B & C are designed to operate at .75 volts for full brightness. 1. Given the above, each lamp will be at its full designed brightness. 2. Unscrewing lamp A will cause it to extinguish with no change in the path of 3,4 and 5. Lamps 2 and 3 will remain at full brightness. 3. With lamp A out of the circuit (unscrewed) lamps B & C will not be affected and will operate at full brightness. 4. Restoring lamp A will cause it to light with no affect to lamps B & C. 5. Unscrewing lamp C will cause it and lamp B to extinguish. (Series circuit) Current through points 3 and 5 will be one half the original current flow from the battery through the full circuit and current flow from point 3 to 4 will be zero. This all assumes the wiring resistance is at zero ohms and the capacity of the battery (in amperes) is adequate to provide the current needed to light all the lamp. I hope this helped with your homework. If you think of it give me some credit!

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