2nd question******************* An experimenter sets up a microscope with a 4.00

Question

2nd question*******************

An experimenter sets up a microscope with a 4.00 mm objective lens. The object distance between the object and the center of the objective lens, d0 = 4.13 mm.

What is:

The image distance(units required) between the objective lens and the image created by the objective, di=_______

The tube length (units required) L=_____

The lateral magnification of the objective Mo=_____

If an eyepiece of focal length 31.3 is used, what is the magnifying power of this microscope? Calculated microscope magnifying power: _______

Again thanks for any help!

Explanation / Answer

Part A)

1/f = 1/do + 1/di

1/4 = 1/4.13 + 1/di

di = 127.1 mm

Part B)

From the picture, L is given as di - fo

L = 127.1 - 4 = 123.1 mm

Part C)

M = di/do

M = 127.1/4.13 = 30.8

Part D)

M = L(250)/(fo)(fe)

M = (123.1)(250)/(4)(31.3)

M = 245.8 (or round to 246)

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